-x^2+4x-0.5=0

Solution for -x^2+4x-0.5=0 equation:

-x^2+4x-0.5=0

We add all the numbers together, and all the variables

-1x^2+4x-0.5=0

a = -1; b = 4; c = -0.5;
Δ = b2-4ac
Δ = 42-4·(-1)·(-0.5)
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-\sqrt{14}}{2*-1}=\frac{-4-\sqrt{14}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+\sqrt{14}}{2*-1}=\frac{-4+\sqrt{14}}{-2}
$